basic subnetting
subnet 101
TCP/IP
0 - 255 = 256
4 -2
8-6
16 -14
32 - 30
64 - 62
128 - 126
256 - class C
example : I need 18 new IPs so:
256 - 32 = 224 since you have to round off to the next highest.
.224 will be the new subnet
therefore I have 30 available to use on the new 224 subnet. 32 + 30 = 62
.32 .33 .34 .35 .36 .37 .38 ....... .62
TCP/IP
0 - 255 = 256
4 -2
8-6
16 -14
32 - 30
64 - 62
128 - 126
256 - class C
example : I need 18 new IPs so:
256 - 32 = 224 since you have to round off to the next highest.
.224 will be the new subnet
therefore I have 30 available to use on the new 224 subnet. 32 + 30 = 62
.32 .33 .34 .35 .36 .37 .38 ....... .62
posted by Rodney at
9:13 PM
0 Comments:
Post a Comment
Subscribe to Post Comments [Atom]
<< Home